Mysql获取指定时间范围数据的各种实例

目录前言1、今天(TO_DAYS())2、今天昨天(TO_DAYS())3.近7天(DATE_SUB())4.本月(DATE_FORMAT())5.上一月(PERIOD_DIFF())6.本季度7.上季度8.本年9.去年10.本周11.上周12.本月13.距今6个月总结
前言 MySQL获取某个时间范围内的数据 TO_DAYS(date)函数。
to_days()：返回从0000年至当前日期的总天数。
表数据：


1、今天(TO_DAYS())

select * from 表名 where to_days(字段名) = to_days(now());

SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) – TO_DAYS(字段名) <= 1

SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(字段名)

SELECT * FROM 表名 WHERE DATE_FORMAT(字段名, ‘%Y%m') = DATE_FORMAT( CURDATE( ) , ‘%Y%m' )

SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , ‘%Y%m' ) , date_format(字段名, ‘%Y%m') ) =1

select * from `表名` where QUARTER(字段名)=QUARTER(now());

select * from `表名` where QUARTER(字段名)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));

select * from `表名` where YEAR(字段名)=YEAR(NOW());

select * from `表名` where year(字段名)=year(date_sub(now(),interval 1 year));

SELECT * FROM 表名 WHERE YEARWEEK(date_format(字段名,'%Y-%m-%d')) = YEARWEEK(now());

SELECT * FROM 表名 WHERE YEARWEEK(date_format(字段名,'%Y-%m-%d')) = YEARWEEK(now())-1;

select * from 表名 where date_format(字段名,'%Y-%m')=date_format(now(),'%Y-%m')

select * from 表名 where 字段名 between date_sub(now(),interval 6 month) and now();